Base | Representation |
---|---|
bin | 111000011001001001… |
… | …1110001110110011101 |
3 | 102120120212220102101121 |
4 | 1300302103301312131 |
5 | 3441004400130023 |
6 | 131344540210541 |
7 | 11515022422615 |
oct | 1606223616635 |
9 | 376525812347 |
10 | 121103130013 |
11 | 473a5618018 |
12 | 1b579239a51 |
13 | b55c8c2918 |
14 | 5c0ba5ba45 |
15 | 323bc58d5d |
hex | 1c324f1d9d |
121103130013 has 2 divisors, whose sum is σ = 121103130014. Its totient is φ = 121103130012.
The previous prime is 121103130007. The next prime is 121103130077. The reversal of 121103130013 is 310031301121.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 102860035524 + 18243094489 = 320718^2 + 135067^2 .
It is an emirp because it is prime and its reverse (310031301121) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 121103130013 - 29 = 121103129501 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (121103140013) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60551565006 + 60551565007.
It is an arithmetic number, because the mean of its divisors is an integer number (60551565007).
Almost surely, 2121103130013 is an apocalyptic number.
It is an amenable number.
121103130013 is a deficient number, since it is larger than the sum of its proper divisors (1).
121103130013 is an equidigital number, since it uses as much as digits as its factorization.
121103130013 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 54, while the sum is 16.
Adding to 121103130013 its reverse (310031301121), we get a palindrome (431134431134).
The spelling of 121103130013 in words is "one hundred twenty-one billion, one hundred three million, one hundred thirty thousand, thirteen".
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