Base | Representation |
---|---|
bin | 10010011110101… |
… | …011111011000001 |
3 | 210121101100211221 |
4 | 102132223323001 |
5 | 1113332042423 |
6 | 50433035041 |
7 | 10453150354 |
oct | 2236537301 |
9 | 717340757 |
10 | 310034113 |
11 | 14a008244 |
12 | 879b5a81 |
13 | 4c30204c |
14 | 2d26629b |
15 | 1c341e5d |
hex | 127abec1 |
310034113 has 2 divisors, whose sum is σ = 310034114. Its totient is φ = 310034112.
The previous prime is 310034111. The next prime is 310034119. The reversal of 310034113 is 311430013.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 308634624 + 1399489 = 17568^2 + 1183^2 .
It is a cyclic number.
It is not a de Polignac number, because 310034113 - 21 = 310034111 is a prime.
It is a super-2 number, since 2×3100341132 = 192242302447393538, which contains 22 as substring.
Together with 310034111, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (310034111) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 155017056 + 155017057.
It is an arithmetic number, because the mean of its divisors is an integer number (155017057).
Almost surely, 2310034113 is an apocalyptic number.
It is an amenable number.
310034113 is a deficient number, since it is larger than the sum of its proper divisors (1).
310034113 is an equidigital number, since it uses as much as digits as its factorization.
310034113 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 108, while the sum is 16.
The square root of 310034113 is about 17607.7855791124. The cubic root of 310034113 is about 676.8147693920.
Adding to 310034113 its reverse (311430013), we get a palindrome (621464126).
The spelling of 310034113 in words is "three hundred ten million, thirty-four thousand, one hundred thirteen".
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