Base | Representation |
---|---|
bin | 11100110111111110… |
… | …110111111110101011 |
3 | 2222000201111101200122 |
4 | 130313332313332223 |
5 | 1001444011001141 |
6 | 22124255153455 |
7 | 2145210440024 |
oct | 346776677653 |
9 | 88021441618 |
10 | 31004000171 |
11 | 1216aa4a241 |
12 | 601321588b |
13 | 2c013a2c41 |
14 | 1701917c4b |
15 | c16d4a64b |
hex | 737fb7fab |
31004000171 has 2 divisors, whose sum is σ = 31004000172. Its totient is φ = 31004000170.
The previous prime is 31004000143. The next prime is 31004000197. The reversal of 31004000171 is 17100040013.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-31004000171 is a prime.
It is a super-2 number, since 2×310040001712 (a number of 22 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (31001000171) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15502000085 + 15502000086.
It is an arithmetic number, because the mean of its divisors is an integer number (15502000086).
Almost surely, 231004000171 is an apocalyptic number.
31004000171 is a deficient number, since it is larger than the sum of its proper divisors (1).
31004000171 is an equidigital number, since it uses as much as digits as its factorization.
31004000171 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 84, while the sum is 17.
Adding to 31004000171 its reverse (17100040013), we get a palindrome (48104040184).
The spelling of 31004000171 in words is "thirty-one billion, four million, one hundred seventy-one", and thus it is an aban number.
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