Base | Representation |
---|---|
bin | 1110000110010101101000… |
… | …10111111101100101110111 |
3 | 11001202222000001020000100112 |
4 | 13003022310113331211313 |
5 | 13030432344112413444 |
6 | 145535030441333235 |
7 | 6346654334535503 |
oct | 703126427754567 |
9 | 131688001200315 |
10 | 31004100122999 |
11 | 9973846276053 |
12 | 358897649721b |
13 | 143b89bcb3c73 |
14 | 79286c16b303 |
15 | 38b74b49169e |
hex | 1c32b45fd977 |
31004100122999 has 2 divisors, whose sum is σ = 31004100123000. Its totient is φ = 31004100122998.
The previous prime is 31004100122993. The next prime is 31004100123043. The reversal of 31004100122999 is 99922100140013.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 31004100122999 - 224 = 31004083345783 is a prime.
It is a super-2 number, since 2×310041001229992 (a number of 28 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (31004100122993) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15502050061499 + 15502050061500.
It is an arithmetic number, because the mean of its divisors is an integer number (15502050061500).
Almost surely, 231004100122999 is an apocalyptic number.
31004100122999 is a deficient number, since it is larger than the sum of its proper divisors (1).
31004100122999 is an equidigital number, since it uses as much as digits as its factorization.
31004100122999 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 34992, while the sum is 41.
The spelling of 31004100122999 in words is "thirty-one trillion, four billion, one hundred million, one hundred twenty-two thousand, nine hundred ninety-nine".
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