31004121 has 4 divisors (see below), whose sum is σ = 41338832. Its totient is φ = 20669412.

The previous prime is 31004119. The next prime is 31004147. The reversal of 31004121 is 12140013.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 12140013 = 3 ⋅4046671.

It is not a de Polignac number, because 31004121 - 2¹ = 31004119 is a prime.

It is a super-2 number, since 2×31004121² = 1922511037965282, which contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 31004097 and 31004106.

It is not an unprimeable number, because it can be changed into a prime (31004101) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5167351 + ... + 5167356.

It is an arithmetic number, because the mean of its divisors is an integer number (10334708).

Almost surely, 2^31004121 is an apocalyptic number.

It is an amenable number.

31004121 is a deficient number, since it is larger than the sum of its proper divisors (10334711).

31004121 is a wasteful number, since it uses less digits than its factorization.

31004121 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 10334710.

The product of its (nonzero) digits is 24, while the sum is 12.

The square root of 31004121 is about 5568.1344272566. The cubic root of 31004121 is about 314.1519846543.

Adding to 31004121 its reverse (12140013), we get a palindrome (43144134).

It can be divided in two parts, 31004 and 121, that added together give a triangular number (31125 = T₂₄₉).

The spelling of 31004121 in words is "thirty-one million, four thousand, one hundred twenty-one".