31004141131 has 2 divisors, whose sum is σ = 31004141132. Its totient is φ = 31004141130.

The previous prime is 31004141117. The next prime is 31004141143. The reversal of 31004141131 is 13114140013.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 31004141131 - 2⁹ = 31004140619 is a prime.

It is a super-2 number, since 2×31004141131² (a number of 22 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 31004141099 and 31004141108.

It is not a weakly prime, because it can be changed into another prime (31004141111) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15502070565 + 15502070566.

It is an arithmetic number, because the mean of its divisors is an integer number (15502070566).

Almost surely, 2^31004141131 is an apocalyptic number.

31004141131 is a deficient number, since it is larger than the sum of its proper divisors (1).

31004141131 is an equidigital number, since it uses as much as digits as its factorization.

31004141131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 144, while the sum is 19.

Adding to 31004141131 its reverse (13114140013), we get a palindrome (44118281144).

The spelling of 31004141131 in words is "thirty-one billion, four million, one hundred forty-one thousand, one hundred thirty-one".