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31004497 is a prime number
BaseRepresentation
bin111011001000…
…1011101010001
32011100012011201
41312101131101
530414120442
63024311201
7524351056
oct166213521
964305151
1031004497
1116557157
12a472501
136567274
14419102d
152ac67b7
hex1d91751

31004497 has 2 divisors, whose sum is σ = 31004498. Its totient is φ = 31004496.

The previous prime is 31004489. The next prime is 31004503. The reversal of 31004497 is 79440013.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 25847056 + 5157441 = 5084^2 + 2271^2 .

It is a cyclic number.

It is not a de Polignac number, because 31004497 - 23 = 31004489 is a prime.

It is a super-2 number, since 2×310044972 = 1922557668446018, which contains 22 as substring.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (31001497) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15502248 + 15502249.

It is an arithmetic number, because the mean of its divisors is an integer number (15502249).

Almost surely, 231004497 is an apocalyptic number.

It is an amenable number.

31004497 is a deficient number, since it is larger than the sum of its proper divisors (1).

31004497 is an equidigital number, since it uses as much as digits as its factorization.

31004497 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3024, while the sum is 28.

The square root of 31004497 is about 5568.1681907069. The cubic root of 31004497 is about 314.1532546002.

The spelling of 31004497 in words is "thirty-one million, four thousand, four hundred ninety-seven".