Base | Representation |
---|---|
bin | 101101000111101100110… |
… | …110111110111110111001 |
3 | 101222102022022002002002121 |
4 | 231013230312332332321 |
5 | 401300110141212040 |
6 | 10332230004401241 |
7 | 440004610553542 |
oct | 55075466767671 |
9 | 11872268062077 |
10 | 3100645257145 |
11 | a95a81461047 |
12 | 420b139a6221 |
13 | 19650ac228b7 |
14 | aa1019214c9 |
15 | 559c543ac4a |
hex | 2d1ecdbefb9 |
3100645257145 has 4 divisors (see below), whose sum is σ = 3720774308580. Its totient is φ = 2480516205712.
The previous prime is 3100645257107. The next prime is 3100645257161. The reversal of 3100645257145 is 5417525460013.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 1549716255376 + 1550929001769 = 1244876^2 + 1245363^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-3100645257145 is a prime.
It is a super-2 number, since 2×31006452571452 (a number of 26 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 310064525710 + ... + 310064525719.
It is an arithmetic number, because the mean of its divisors is an integer number (930193577145).
Almost surely, 23100645257145 is an apocalyptic number.
It is an amenable number.
3100645257145 is a deficient number, since it is larger than the sum of its proper divisors (620129051435).
3100645257145 is an equidigital number, since it uses as much as digits as its factorization.
3100645257145 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 620129051434.
The product of its (nonzero) digits is 504000, while the sum is 43.
The spelling of 3100645257145 in words is "three trillion, one hundred billion, six hundred forty-five million, two hundred fifty-seven thousand, one hundred forty-five".
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