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31007985750253 is a prime number
BaseRepresentation
bin1110000110011100110111…
…11110011101000011101101
311001210100000211201022220001
413003032123332131003231
513031013323323002003
6145540512204024301
76350152536036031
oct703163376350355
9131710024638801
1031007985750253
11997545a641346
12358967b832091
13143c06accbba5
14792b1a22c1c1
1538b8c767361d
hex1c339bf9d0ed

31007985750253 has 2 divisors, whose sum is σ = 31007985750254. Its totient is φ = 31007985750252.

The previous prime is 31007985750233. The next prime is 31007985750263. The reversal of 31007985750253 is 35205758970013.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 28860242741929 + 2147743008324 = 5372173^2 + 1465518^2 .

It is a cyclic number.

It is not a de Polignac number, because 31007985750253 - 225 = 31007952195821 is a prime.

It is a super-2 number, since 2×310079857502532 (a number of 28 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 31007985750194 and 31007985750203.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (31007985750233) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15503992875126 + 15503992875127.

It is an arithmetic number, because the mean of its divisors is an integer number (15503992875127).

Almost surely, 231007985750253 is an apocalyptic number.

It is an amenable number.

31007985750253 is a deficient number, since it is larger than the sum of its proper divisors (1).

31007985750253 is an equidigital number, since it uses as much as digits as its factorization.

31007985750253 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 7938000, while the sum is 55.

The spelling of 31007985750253 in words is "thirty-one trillion, seven billion, nine hundred eighty-five million, seven hundred fifty thousand, two hundred fifty-three".