Base | Representation |
---|---|
bin | 1110000110100110100110… |
… | …11111100001001010011101 |
3 | 11001210211112002002000211021 |
4 | 13003103103133201022131 |
5 | 13031110024301210442 |
6 | 145543134543324141 |
7 | 6350426210406424 |
oct | 703232337411235 |
9 | 131724462060737 |
10 | 31013212131997 |
11 | 99776a18102a7 |
12 | 358a699bb0651 |
13 | 143c6c1a20b74 |
14 | 7930943bc2bb |
15 | 38bad13e5e67 |
hex | 1c34d37e129d |
31013212131997 has 2 divisors, whose sum is σ = 31013212131998. Its totient is φ = 31013212131996.
The previous prime is 31013212131989. The next prime is 31013212132013. The reversal of 31013212131997 is 79913121231013.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 23905117589796 + 7108094542201 = 4889286^2 + 2666101^2 .
It is a cyclic number.
It is not a de Polignac number, because 31013212131997 - 23 = 31013212131989 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (31013212131197) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15506606065998 + 15506606065999.
It is an arithmetic number, because the mean of its divisors is an integer number (15506606065999).
Almost surely, 231013212131997 is an apocalyptic number.
It is an amenable number.
31013212131997 is a deficient number, since it is larger than the sum of its proper divisors (1).
31013212131997 is an equidigital number, since it uses as much as digits as its factorization.
31013212131997 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 61236, while the sum is 43.
The spelling of 31013212131997 in words is "thirty-one trillion, thirteen billion, two hundred twelve million, one hundred thirty-one thousand, nine hundred ninety-seven".
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