Base | Representation |
---|---|
bin | 1001000001110100001… |
… | …01101000111010011101 |
3 | 1002122201012222122111001 |
4 | 10200322011220322131 |
5 | 20040303310432031 |
6 | 354302020030301 |
7 | 31261230132412 |
oct | 4407205507235 |
9 | 1078635878431 |
10 | 310212202141 |
11 | 10a618778986 |
12 | 50155532391 |
13 | 2333978637a |
14 | 1102b542109 |
15 | 8108ed6861 |
hex | 483a168e9d |
310212202141 has 2 divisors, whose sum is σ = 310212202142. Its totient is φ = 310212202140.
The previous prime is 310212202109. The next prime is 310212202147. The reversal of 310212202141 is 141202212013.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 221601796516 + 88610405625 = 470746^2 + 297675^2 .
It is a cyclic number.
It is not a de Polignac number, because 310212202141 - 25 = 310212202109 is a prime.
It is a super-2 number, since 2×3102122021412 (a number of 24 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (310212202147) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 155106101070 + 155106101071.
It is an arithmetic number, because the mean of its divisors is an integer number (155106101071).
Almost surely, 2310212202141 is an apocalyptic number.
It is an amenable number.
310212202141 is a deficient number, since it is larger than the sum of its proper divisors (1).
310212202141 is an equidigital number, since it uses as much as digits as its factorization.
310212202141 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 192, while the sum is 19.
Adding to 310212202141 its reverse (141202212013), we get a palindrome (451414414154).
The spelling of 310212202141 in words is "three hundred ten billion, two hundred twelve million, two hundred two thousand, one hundred forty-one".
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