Base | Representation |
---|---|
bin | 100011010001000110001100… |
… | …0010001001000011000010011 |
3 | 1111200101002000001010122011101 |
4 | 1012202030120101020120103 |
5 | 311130012221032012042 |
6 | 3015433520041325231 |
7 | 122225102401421305 |
oct | 10642143021103023 |
9 | 1450332001118141 |
10 | 310213010032147 |
11 | 8a930664a21422 |
12 | 2a961439496817 |
13 | 10412c66054581 |
14 | 5686565863975 |
15 | 25ce543eaa6b7 |
hex | 11a2318448613 |
310213010032147 has 2 divisors, whose sum is σ = 310213010032148. Its totient is φ = 310213010032146.
The previous prime is 310213010032111. The next prime is 310213010032169. The reversal of 310213010032147 is 741230010312013.
It is a strong prime.
It is an emirp because it is prime and its reverse (741230010312013) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-310213010032147 is a prime.
It is a super-2 number, since 2×3102130100321472 (a number of 30 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (310213010032747) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 155106505016073 + 155106505016074.
It is an arithmetic number, because the mean of its divisors is an integer number (155106505016074).
Almost surely, 2310213010032147 is an apocalyptic number.
310213010032147 is a deficient number, since it is larger than the sum of its proper divisors (1).
310213010032147 is an equidigital number, since it uses as much as digits as its factorization.
310213010032147 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 3024, while the sum is 28.
The spelling of 310213010032147 in words is "three hundred ten trillion, two hundred thirteen billion, ten million, thirty-two thousand, one hundred forty-seven".
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