Base | Representation |
---|---|
bin | 1001000001110100010… |
… | …00110100000101100101 |
3 | 1002122201021112221001021 |
4 | 10200322020310011211 |
5 | 20040304014044331 |
6 | 354302045531141 |
7 | 31261240166560 |
oct | 4407210640545 |
9 | 1078637487037 |
10 | 310213034341 |
11 | 10a619197151 |
12 | 50155873ab1 |
13 | 233399b80b2 |
14 | 1102b6bb4d7 |
15 | 81090ed211 |
hex | 483a234165 |
310213034341 has 4 divisors (see below), whose sum is σ = 354529182112. Its totient is φ = 265896886572.
The previous prime is 310213034317. The next prime is 310213034347. The reversal of 310213034341 is 143430312013.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 143430312013 = 41 ⋅3498300293.
It is a cyclic number.
It is not a de Polignac number, because 310213034341 - 25 = 310213034309 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (310213034347) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 22158073875 + ... + 22158073888.
It is an arithmetic number, because the mean of its divisors is an integer number (88632295528).
Almost surely, 2310213034341 is an apocalyptic number.
It is an amenable number.
310213034341 is a deficient number, since it is larger than the sum of its proper divisors (44316147771).
310213034341 is an equidigital number, since it uses as much as digits as its factorization.
310213034341 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 44316147770.
The product of its (nonzero) digits is 2592, while the sum is 25.
Adding to 310213034341 its reverse (143430312013), we get a palindrome (453643346354).
The spelling of 310213034341 in words is "three hundred ten billion, two hundred thirteen million, thirty-four thousand, three hundred forty-one".
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