Base | Representation |
---|---|
bin | 101101001010000000011… |
… | …100000010110111010001 |
3 | 101222122200212001011220011 |
4 | 231022000130002313101 |
5 | 401320143013114441 |
6 | 10333315413114521 |
7 | 440123144122333 |
oct | 55120034026721 |
9 | 11878625034804 |
10 | 3103121223121 |
11 | a97032039a17 |
12 | 4214a5028a41 |
13 | 196813b8871a |
14 | aa2986b7453 |
15 | 55abc9ba581 |
hex | 2d280702dd1 |
3103121223121 has 4 divisors (see below), whose sum is σ = 3107830057200. Its totient is φ = 3098412389044.
The previous prime is 3103121223101. The next prime is 3103121223143. The reversal of 3103121223121 is 1213221213013.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 3103121223121 - 25 = 3103121223089 is a prime.
It is a super-2 number, since 2×31031212231212 (a number of 26 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 3103121223092 and 3103121223101.
It is not an unprimeable number, because it can be changed into a prime (3103121223101) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2354416051 + ... + 2354417368.
It is an arithmetic number, because the mean of its divisors is an integer number (776957514300).
Almost surely, 23103121223121 is an apocalyptic number.
It is an amenable number.
3103121223121 is a deficient number, since it is larger than the sum of its proper divisors (4708834079).
3103121223121 is an equidigital number, since it uses as much as digits as its factorization.
3103121223121 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4708834078.
The product of its (nonzero) digits is 432, while the sum is 22.
Adding to 3103121223121 its reverse (1213221213013), we get a palindrome (4316342436134).
The spelling of 3103121223121 in words is "three trillion, one hundred three billion, one hundred twenty-one million, two hundred twenty-three thousand, one hundred twenty-one".
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