Base | Representation |
---|---|
bin | 101101001010010011100… |
… | …111101001000110110011 |
3 | 101222200112021120200120011 |
4 | 231022103213221012303 |
5 | 401321322403433301 |
6 | 10333411350355351 |
7 | 440134132336201 |
oct | 55122347510663 |
9 | 11880467520504 |
10 | 3103443030451 |
11 | a97187758595 |
12 | 42157495bb57 |
13 | 19686575046a |
14 | aa2c9326071 |
15 | 55adad85a51 |
hex | 2d2939e91b3 |
3103443030451 has 2 divisors, whose sum is σ = 3103443030452. Its totient is φ = 3103443030450.
The previous prime is 3103443030449. The next prime is 3103443030487. The reversal of 3103443030451 is 1540303443013.
3103443030451 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is an emirp because it is prime and its reverse (1540303443013) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 3103443030451 - 21 = 3103443030449 is a prime.
Together with 3103443030449, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (3103443030251) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1551721515225 + 1551721515226.
It is an arithmetic number, because the mean of its divisors is an integer number (1551721515226).
Almost surely, 23103443030451 is an apocalyptic number.
3103443030451 is a deficient number, since it is larger than the sum of its proper divisors (1).
3103443030451 is an equidigital number, since it uses as much as digits as its factorization.
3103443030451 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 25920, while the sum is 31.
Adding to 3103443030451 its reverse (1540303443013), we get a palindrome (4643746473464).
The spelling of 3103443030451 in words is "three trillion, one hundred three billion, four hundred forty-three million, thirty thousand, four hundred fifty-one".
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