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3104113114 = 21552056557
BaseRepresentation
bin1011100100000101…
…0000000111011010
322000022221021200101
42321001100013122
522324123104424
61232003530014
7136631345314
oct27101200732
98008837611
103104113114
111353211143
1272768990a
133a613822b
142163887b4
151327ac344
hexb90501da

3104113114 has 4 divisors (see below), whose sum is σ = 4656169674. Its totient is φ = 1552056556.

The previous prime is 3104113057. The next prime is 3104113123. The reversal of 3104113114 is 4113114013.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 4113114013 = 10273400381.

It can be written as a sum of positive squares in only one way, i.e., 2604367089 + 499746025 = 51033^2 + 22355^2 .

It is a junction number, because it is equal to n+sod(n) for n = 3104113091 and 3104113100.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 776028277 + ... + 776028280.

Almost surely, 23104113114 is an apocalyptic number.

3104113114 is a deficient number, since it is larger than the sum of its proper divisors (1552056560).

3104113114 is a wasteful number, since it uses less digits than its factorization.

3104113114 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1552056559.

The product of its (nonzero) digits is 144, while the sum is 19.

The square root of 3104113114 is about 55714.5682384778. The cubic root of 3104113114 is about 1458.7443250685.

Adding to 3104113114 its reverse (4113114013), we get a palindrome (7217227127).

The spelling of 3104113114 in words is "three billion, one hundred four million, one hundred thirteen thousand, one hundred fourteen".

Divisors: 1 2 1552056557 3104113114