Base | Representation |
---|---|
bin | 101101001010111100110… |
… | …100101011100000011101 |
3 | 101222202022110100112100001 |
4 | 231022330310223200131 |
5 | 401324231341022023 |
6 | 10334004123134301 |
7 | 440160225215155 |
oct | 55127464534035 |
9 | 11882273315301 |
10 | 3104134314013 |
11 | a97501994117 |
12 | 421728374391 |
13 | 196945a2a2a5 |
14 | aa353071765 |
15 | 55b2b8d56ad |
hex | 2d2bcd2b81d |
3104134314013 has 2 divisors, whose sum is σ = 3104134314014. Its totient is φ = 3104134314012.
The previous prime is 3104134314007. The next prime is 3104134314067.
3104134314013 is nontrivially palindromic in base 10.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 2860150675204 + 243983638809 = 1691198^2 + 493947^2 .
It is a palprime.
It is a cyclic number.
It is not a de Polignac number, because 3104134314013 - 25 = 3104134313981 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (3104134311013) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1552067157006 + 1552067157007.
It is an arithmetic number, because the mean of its divisors is an integer number (1552067157007).
Almost surely, 23104134314013 is an apocalyptic number.
It is an amenable number.
3104134314013 is a deficient number, since it is larger than the sum of its proper divisors (1).
3104134314013 is an equidigital number, since it uses as much as digits as its factorization.
3104134314013 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5184, while the sum is 28.
The spelling of 3104134314013 in words is "three trillion, one hundred four billion, one hundred thirty-four million, three hundred fourteen thousand, thirteen".
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