Base | Representation |
---|---|
bin | 1110000111101011101101… |
… | …11000111001110111011001 |
3 | 11001221101021201022010210111 |
4 | 13003311312320321313121 |
5 | 13032212020140230403 |
6 | 150012152244244321 |
7 | 6353211464363512 |
oct | 703656670716731 |
9 | 131841251263714 |
10 | 31050313211353 |
11 | 9991400367357 |
12 | 35959130a06a1 |
13 | 144305531ca67 |
14 | 794bb3975a09 |
15 | 38ca5365356d |
hex | 1c3d76e39dd9 |
31050313211353 has 8 divisors (see below), whose sum is σ = 31152942551808. Its totient is φ = 30947693535504.
The previous prime is 31050313211317. The next prime is 31050313211371. The reversal of 31050313211353 is 35311231305013.
It is a happy number.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-31050313211353 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (31050313211383) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 4048575 + ... + 8859547.
It is an arithmetic number, because the mean of its divisors is an integer number (3894117818976).
Almost surely, 231050313211353 is an apocalyptic number.
It is an amenable number.
31050313211353 is a deficient number, since it is larger than the sum of its proper divisors (102629340455).
31050313211353 is a wasteful number, since it uses less digits than its factorization.
31050313211353 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4832303.
The product of its (nonzero) digits is 12150, while the sum is 31.
Adding to 31050313211353 its reverse (35311231305013), we get a palindrome (66361544516366).
The spelling of 31050313211353 in words is "thirty-one trillion, fifty billion, three hundred thirteen million, two hundred eleven thousand, three hundred fifty-three".
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