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31053052433 = 132388696341
BaseRepresentation
bin11100111010111001…
…111111101000010001
32222011010210111202002
4130322321333220101
51002044040134213
622133210403345
72146344406364
oct347271775021
988133714662
1031053052433
11121957029a7
126027730555
132c0b5b8b50
1417082460db
15c1b2d9658
hex73ae7fa11

31053052433 has 4 divisors (see below), whose sum is σ = 33441748788. Its totient is φ = 28664356080.

The previous prime is 31053052423. The next prime is 31053052487. The reversal of 31053052433 is 33425035013.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 11949113344 + 19103939089 = 109312^2 + 138217^2 .

It is a cyclic number.

It is not a de Polignac number, because 31053052433 - 228 = 30784616977 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 31053052396 and 31053052405.

It is not an unprimeable number, because it can be changed into a prime (31053052403) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1194348158 + ... + 1194348183.

It is an arithmetic number, because the mean of its divisors is an integer number (8360437197).

Almost surely, 231053052433 is an apocalyptic number.

It is an amenable number.

31053052433 is a deficient number, since it is larger than the sum of its proper divisors (2388696355).

31053052433 is a wasteful number, since it uses less digits than its factorization.

31053052433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2388696354.

The product of its (nonzero) digits is 16200, while the sum is 29.

Adding to 31053052433 its reverse (33425035013), we get a palindrome (64478087446).

The spelling of 31053052433 in words is "thirty-one billion, fifty-three million, fifty-two thousand, four hundred thirty-three".

Divisors: 1 13 2388696341 31053052433