Base | Representation |
---|---|
bin | 1001000011010010000… |
… | …11011000110011110001 |
3 | 1002201202010122002110021 |
4 | 10201221003120303301 |
5 | 20043412014003131 |
6 | 354512124203441 |
7 | 31316605403362 |
oct | 4415103306361 |
9 | 1081663562407 |
10 | 311000141041 |
11 | 10a992521057 |
12 | 50335399581 |
13 | 23433aa54c5 |
14 | 110a404bb69 |
15 | 8153279e11 |
hex | 48690d8cf1 |
311000141041 has 2 divisors, whose sum is σ = 311000141042. Its totient is φ = 311000141040.
The previous prime is 311000140993. The next prime is 311000141083. The reversal of 311000141041 is 140141000113.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 308974781025 + 2025360016 = 555855^2 + 45004^2 .
It is a cyclic number.
It is not a de Polignac number, because 311000141041 - 211 = 311000138993 is a prime.
It is not a weakly prime, because it can be changed into another prime (311000441041) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 155500070520 + 155500070521.
It is an arithmetic number, because the mean of its divisors is an integer number (155500070521).
Almost surely, 2311000141041 is an apocalyptic number.
It is an amenable number.
311000141041 is a deficient number, since it is larger than the sum of its proper divisors (1).
311000141041 is an equidigital number, since it uses as much as digits as its factorization.
311000141041 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 48, while the sum is 16.
Adding to 311000141041 its reverse (140141000113), we get a palindrome (451141141154).
The spelling of 311000141041 in words is "three hundred eleven billion, one hundred forty-one thousand, forty-one".
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