Base | Representation |
---|---|
bin | 1110001001001000100000… |
… | …10101010101110001110111 |
3 | 11002010010212200112222222202 |
4 | 13010210100111111301313 |
5 | 13034021032322020043 |
6 | 150051111542415115 |
7 | 6356624161101656 |
oct | 704442025256167 |
9 | 132103780488882 |
10 | 31100132220023 |
11 | 9a0054594a999 |
12 | 35a34b743149b |
13 | 144796472c609 |
14 | 79737c23119d |
15 | 38debc1961b8 |
hex | 1c4910555c77 |
31100132220023 has 2 divisors, whose sum is σ = 31100132220024. Its totient is φ = 31100132220022.
The previous prime is 31100132220007. The next prime is 31100132220067. The reversal of 31100132220023 is 32002223100113.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 31100132220023 - 24 = 31100132220007 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 31100132219977 and 31100132220004.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (31100132223023) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15550066110011 + 15550066110012.
It is an arithmetic number, because the mean of its divisors is an integer number (15550066110012).
Almost surely, 231100132220023 is an apocalyptic number.
31100132220023 is a deficient number, since it is larger than the sum of its proper divisors (1).
31100132220023 is an equidigital number, since it uses as much as digits as its factorization.
31100132220023 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 432, while the sum is 20.
Adding to 31100132220023 its reverse (32002223100113), we get a palindrome (63102355320136).
The spelling of 31100132220023 in words is "thirty-one trillion, one hundred billion, one hundred thirty-two million, two hundred twenty thousand, twenty-three".
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