Base | Representation |
---|---|
bin | 101101010000011011101… |
… | …101000100010100111111 |
3 | 102000022111201102022212011 |
4 | 231100123231010110333 |
5 | 401423310401340333 |
6 | 10340420213552051 |
7 | 440456136233563 |
oct | 55203355042477 |
9 | 12008451368764 |
10 | 3110021121343 |
11 | a99a52932644 |
12 | 4228ab945627 |
13 | 197373513736 |
14 | aa750c176a3 |
15 | 55d7360e9cd |
hex | 2d41bb4453f |
3110021121343 has 2 divisors, whose sum is σ = 3110021121344. Its totient is φ = 3110021121342.
The previous prime is 3110021121301. The next prime is 3110021121391. The reversal of 3110021121343 is 3431211200113.
3110021121343 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 3110021121343 - 225 = 3109987566911 is a prime.
It is a super-2 number, since 2×31100211213432 (a number of 26 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (3110021161343) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1555010560671 + 1555010560672.
It is an arithmetic number, because the mean of its divisors is an integer number (1555010560672).
Almost surely, 23110021121343 is an apocalyptic number.
3110021121343 is a deficient number, since it is larger than the sum of its proper divisors (1).
3110021121343 is an equidigital number, since it uses as much as digits as its factorization.
3110021121343 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 432, while the sum is 22.
Adding to 3110021121343 its reverse (3431211200113), we get a palindrome (6541232321456).
The spelling of 3110021121343 in words is "three trillion, one hundred ten billion, twenty-one million, one hundred twenty-one thousand, three hundred forty-three".
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