Base | Representation |
---|---|
bin | 11100111101101101… |
… | …111101100111100001 |
3 | 2222021102120101100120 |
4 | 130331231331213201 |
5 | 1002143124330423 |
6 | 22142013510453 |
7 | 2150456410551 |
oct | 347555754741 |
9 | 88242511316 |
10 | 31100230113 |
11 | 1220a2a6217 |
12 | 603b4a2429 |
13 | 2c182c6734 |
14 | 1710607161 |
15 | c20507ee3 |
hex | 73db7d9e1 |
31100230113 has 32 divisors (see below), whose sum is σ = 42713147904. Its totient is φ = 20121564672.
The previous prime is 31100230103. The next prime is 31100230127. The reversal of 31100230113 is 31103200113.
It is not a de Polignac number, because 31100230113 - 210 = 31100229089 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 31100230092 and 31100230101.
It is not an unprimeable number, because it can be changed into a prime (31100230103) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 4422306 + ... + 4429332.
It is an arithmetic number, because the mean of its divisors is an integer number (1334785872).
Almost surely, 231100230113 is an apocalyptic number.
It is an amenable number.
31100230113 is a deficient number, since it is larger than the sum of its proper divisors (11612917791).
31100230113 is a wasteful number, since it uses less digits than its factorization.
31100230113 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 7421.
The product of its (nonzero) digits is 54, while the sum is 15.
Adding to 31100230113 its reverse (31103200113), we get a palindrome (62203430226).
The spelling of 31100230113 in words is "thirty-one billion, one hundred million, two hundred thirty thousand, one hundred thirteen".
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