Base | Representation |
---|---|
bin | 101101010000011100010… |
… | …000000101001101110111 |
3 | 102000022112100200122122021 |
4 | 231100130100011031313 |
5 | 401423320224100043 |
6 | 10340421142414011 |
7 | 440456310242563 |
oct | 55203420051567 |
9 | 12008470618567 |
10 | 3110030300023 |
11 | a99a58031729 |
12 | 4228b2a31307 |
13 | 1973753a84ca |
14 | aa7521266a3 |
15 | 55d743243ed |
hex | 2d41c405377 |
3110030300023 has 2 divisors, whose sum is σ = 3110030300024. Its totient is φ = 3110030300022.
The previous prime is 3110030299963. The next prime is 3110030300063. The reversal of 3110030300023 is 3200030300113.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-3110030300023 is a prime.
It is a super-3 number, since 3×31100303000233 (a number of 38 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (3110030300063) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1555015150011 + 1555015150012.
It is an arithmetic number, because the mean of its divisors is an integer number (1555015150012).
Almost surely, 23110030300023 is an apocalyptic number.
3110030300023 is a deficient number, since it is larger than the sum of its proper divisors (1).
3110030300023 is an equidigital number, since it uses as much as digits as its factorization.
3110030300023 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 162, while the sum is 16.
Adding to 3110030300023 its reverse (3200030300113), we get a palindrome (6310060600136).
The spelling of 3110030300023 in words is "three trillion, one hundred ten billion, thirty million, three hundred thousand, twenty-three".
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