Base | Representation |
---|---|
bin | 1110001001001010010100… |
… | …01100100101001000010011 |
3 | 11002010020101100020211200122 |
4 | 13010211022030211020103 |
5 | 13034030024332032011 |
6 | 150051352141540455 |
7 | 6356660216442341 |
oct | 704451214451023 |
9 | 132106340224618 |
10 | 31101103002131 |
11 | 9a009a3927958 |
12 | 35a372857472b |
13 | 1447a8a8a97b6 |
14 | 797431134991 |
15 | 38e0275053db |
hex | 1c494a325213 |
31101103002131 has 2 divisors, whose sum is σ = 31101103002132. Its totient is φ = 31101103002130.
The previous prime is 31101103002107. The next prime is 31101103002163. The reversal of 31101103002131 is 13120030110113.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 31101103002131 - 222 = 31101098807827 is a prime.
It is a super-2 number, since 2×311011030021312 (a number of 28 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (31101103002331) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15550551501065 + 15550551501066.
It is an arithmetic number, because the mean of its divisors is an integer number (15550551501066).
Almost surely, 231101103002131 is an apocalyptic number.
31101103002131 is a deficient number, since it is larger than the sum of its proper divisors (1).
31101103002131 is an equidigital number, since it uses as much as digits as its factorization.
31101103002131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 54, while the sum is 17.
Adding to 31101103002131 its reverse (13120030110113), we get a palindrome (44221133112244).
The spelling of 31101103002131 in words is "thirty-one trillion, one hundred one billion, one hundred three million, two thousand, one hundred thirty-one".
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