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31101213001 = 257208158153
BaseRepresentation
bin11100111101110001…
…101101100101001001
32222021111102022121211
4130331301231211021
51002143402304001
622142050533121
72150500643245
oct347561554511
988244368554
1031101213001
111220a907721
12603b8971a1
132c1857bc21
1417107c1425
15c2064e351
hex73dc6d949

31101213001 has 8 divisors (see below), whose sum is σ = 31237770024. Its totient is φ = 30964776960.

The previous prime is 31101212971. The next prime is 31101213037. The reversal of 31101213001 is 10031210113.

It can be written as a sum of positive squares in 4 ways, for example, as 2438384400 + 28662828601 = 49380^2 + 169301^2 .

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 31101213001 - 25 = 31101212969 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (31101213041) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 505741 + ... + 563893.

It is an arithmetic number, because the mean of its divisors is an integer number (3904721253).

Almost surely, 231101213001 is an apocalyptic number.

It is an amenable number.

31101213001 is a deficient number, since it is larger than the sum of its proper divisors (136557023).

31101213001 is a wasteful number, since it uses less digits than its factorization.

31101213001 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 60491.

The product of its (nonzero) digits is 18, while the sum is 13.

Adding to 31101213001 its reverse (10031210113), we get a palindrome (41132423114).

The spelling of 31101213001 in words is "thirty-one billion, one hundred one million, two hundred thirteen thousand, one".

Divisors: 1 257 2081 58153 534817 14945321 121016393 31101213001