Base | Representation |
---|---|
bin | 11100111101110010… |
… | …000110001101000001 |
3 | 2222021111121102222020 |
4 | 130331302012031001 |
5 | 1002143414020412 |
6 | 22142053032053 |
7 | 2150501543265 |
oct | 347562061501 |
9 | 88244542866 |
10 | 31101313857 |
11 | 1220a976479 |
12 | 603b925629 |
13 | 2c185b5ac3 |
14 | 171080a0a5 |
15 | c2066e18c |
hex | 73dc86341 |
31101313857 has 4 divisors (see below), whose sum is σ = 41468418480. Its totient is φ = 20734209236.
The previous prime is 31101313853. The next prime is 31101313909. The reversal of 31101313857 is 75831310113.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 31101313857 - 22 = 31101313853 is a prime.
It is not an unprimeable number, because it can be changed into a prime (31101313853) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5183552307 + ... + 5183552312.
It is an arithmetic number, because the mean of its divisors is an integer number (10367104620).
Almost surely, 231101313857 is an apocalyptic number.
It is an amenable number.
31101313857 is a deficient number, since it is larger than the sum of its proper divisors (10367104623).
31101313857 is a wasteful number, since it uses less digits than its factorization.
31101313857 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 10367104622.
The product of its (nonzero) digits is 7560, while the sum is 33.
The spelling of 31101313857 in words is "thirty-one billion, one hundred one million, three hundred thirteen thousand, eight hundred fifty-seven".
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