Base | Representation |
---|---|
bin | 101101010000100111000… |
… | …101010000001111110001 |
3 | 102000100000000121112020012 |
4 | 231100213011100033301 |
5 | 401424203233322433 |
6 | 10340451153224305 |
7 | 440463644615303 |
oct | 55204705201761 |
9 | 12010000545205 |
10 | 3110212010993 |
11 | a9a04066288a |
12 | 422943862095 |
13 | 1973a3c2b0a9 |
14 | aa76c307973 |
15 | 55d85269848 |
hex | 2d4271503f1 |
3110212010993 has 2 divisors, whose sum is σ = 3110212010994. Its totient is φ = 3110212010992.
The previous prime is 3110212010987. The next prime is 3110212011029. The reversal of 3110212010993 is 3990102120113.
It is a happy number.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 2491813788304 + 618398222689 = 1578548^2 + 786383^2 .
It is a cyclic number.
It is not a de Polignac number, because 3110212010993 - 222 = 3110207816689 is a prime.
It is not a weakly prime, because it can be changed into another prime (3110212010953) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1555106005496 + 1555106005497.
It is an arithmetic number, because the mean of its divisors is an integer number (1555106005497).
Almost surely, 23110212010993 is an apocalyptic number.
It is an amenable number.
3110212010993 is a deficient number, since it is larger than the sum of its proper divisors (1).
3110212010993 is an equidigital number, since it uses as much as digits as its factorization.
3110212010993 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2916, while the sum is 32.
The spelling of 3110212010993 in words is "three trillion, one hundred ten billion, two hundred twelve million, ten thousand, nine hundred ninety-three".
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