Base | Representation |
---|---|
bin | 101101010000100111000… |
… | …110000001010111111111 |
3 | 102000100000000222202021011 |
4 | 231100213012001113333 |
5 | 401424203311242343 |
6 | 10340451201420051 |
7 | 440463646414054 |
oct | 55204706012777 |
9 | 12010000882234 |
10 | 3110212212223 |
11 | a9a04078aa96 |
12 | 42294393a627 |
13 | 1973a3c9b86c |
14 | aa76c35b02b |
15 | 55d852a929d |
hex | 2d4271815ff |
3110212212223 has 2 divisors, whose sum is σ = 3110212212224. Its totient is φ = 3110212212222.
The previous prime is 3110212212167. The next prime is 3110212212251. The reversal of 3110212212223 is 3222122120113.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 3110212212223 - 213 = 3110212204031 is a prime.
It is a super-2 number, since 2×31102122122232 (a number of 26 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 3110212212194 and 3110212212203.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (3110212219223) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1555106106111 + 1555106106112.
It is an arithmetic number, because the mean of its divisors is an integer number (1555106106112).
Almost surely, 23110212212223 is an apocalyptic number.
3110212212223 is a deficient number, since it is larger than the sum of its proper divisors (1).
3110212212223 is an equidigital number, since it uses as much as digits as its factorization.
3110212212223 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 576, while the sum is 22.
Adding to 3110212212223 its reverse (3222122120113), we get a palindrome (6332334332336).
The spelling of 3110212212223 in words is "three trillion, one hundred ten billion, two hundred twelve million, two hundred twelve thousand, two hundred twenty-three".
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