Base | Representation |
---|---|
bin | 1110001001001100001110… |
… | …11011100010000101010111 |
3 | 11002010100000221100121022201 |
4 | 13010212013123202011113 |
5 | 13034034130331110431 |
6 | 150052042121105331 |
7 | 6360024532551205 |
oct | 704460733420527 |
9 | 132110027317281 |
10 | 31102130331991 |
11 | 9a01380817aa4 |
12 | 35a3974628247 |
13 | 1447bc26954a4 |
14 | 7974cb758075 |
15 | 38e0877d4461 |
hex | 1c49876e2157 |
31102130331991 has 2 divisors, whose sum is σ = 31102130331992. Its totient is φ = 31102130331990.
The previous prime is 31102130331977. The next prime is 31102130332079. The reversal of 31102130331991 is 19913303120113.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 31102130331991 - 211 = 31102130329943 is a prime.
It is a super-2 number, since 2×311021303319912 (a number of 28 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 31102130331991.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (31102130331901) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15551065165995 + 15551065165996.
It is an arithmetic number, because the mean of its divisors is an integer number (15551065165996).
Almost surely, 231102130331991 is an apocalyptic number.
31102130331991 is a deficient number, since it is larger than the sum of its proper divisors (1).
31102130331991 is an equidigital number, since it uses as much as digits as its factorization.
31102130331991 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 13122, while the sum is 37.
The spelling of 31102130331991 in words is "thirty-one trillion, one hundred two billion, one hundred thirty million, three hundred thirty-one thousand, nine hundred ninety-one".
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