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3110220131 is a prime number
BaseRepresentation
bin1011100101100010…
…0011000101100011
322000202102112221012
42321120203011203
522332204021011
61232342451135
7140034302114
oct27130430543
98022375835
103110220131
111356702467
12729733aab
133a7495b55
142170d820b
151330b6a8b
hexb9623163

3110220131 has 2 divisors, whose sum is σ = 3110220132. Its totient is φ = 3110220130.

The previous prime is 3110220121. The next prime is 3110220133. The reversal of 3110220131 is 1310220113.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 3110220131 - 218 = 3109957987 is a prime.

It is a super-2 number, since 2×31102201312 = 19346938526555314322, which contains 22 as substring.

It is a Sophie Germain prime.

Together with 3110220133, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (3110220133) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1555110065 + 1555110066.

It is an arithmetic number, because the mean of its divisors is an integer number (1555110066).

Almost surely, 23110220131 is an apocalyptic number.

3110220131 is a deficient number, since it is larger than the sum of its proper divisors (1).

3110220131 is an equidigital number, since it uses as much as digits as its factorization.

3110220131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 36, while the sum is 14.

The square root of 3110220131 is about 55769.3475934585. The cubic root of 3110220131 is about 1459.7003405457.

Adding to 3110220131 its reverse (1310220113), we get a palindrome (4420440244).

The spelling of 3110220131 in words is "three billion, one hundred ten million, two hundred twenty thousand, one hundred thirty-one".