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311022220130 = 25593145336097
BaseRepresentation
bin1001000011010100101…
…11100111001101100010
31002201210200011211021022
410201222113213031202
520043433142021010
6354514233325442
731320264152036
oct4415227471542
91081720154238
10311022220130
1110a9a3a31436
1250340866882
132343853605b
14110a6d581c6
15815518bd55
hex486a5e7362

311022220130 has 32 divisors (see below), whose sum is σ = 561185572464. Its totient is φ = 124110176256.

The previous prime is 311022220049. The next prime is 311022220183. The reversal of 311022220130 is 31022220113.

It can be written as a sum of positive squares in 8 ways, for example, as 190777641961 + 120244578169 = 436781^2 + 346763^2 .

It is a junction number, because it is equal to n+sod(n) for n = 311022220099 and 311022220108.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 8598242 + ... + 8634338.

Almost surely, 2311022220130 is an apocalyptic number.

311022220130 is a deficient number, since it is larger than the sum of its proper divisors (250163352334).

311022220130 is a wasteful number, since it uses less digits than its factorization.

311022220130 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 38150.

The product of its (nonzero) digits is 144, while the sum is 17.

Subtracting from 311022220130 its sum of digits (17), we obtain a palindrome (311022220113).

Adding to 311022220130 its reverse (31022220113), we get a palindrome (342044440243).

The spelling of 311022220130 in words is "three hundred eleven billion, twenty-two million, two hundred twenty thousand, one hundred thirty".

Divisors: 1 2 5 10 593 1186 1453 2906 2965 5930 7265 14530 36097 72194 180485 360970 861629 1723258 4308145 8616290 21405521 42811042 52448941 104897882 107027605 214055210 262244705 524489410 31102222013 62204444026 155511110065 311022220130