Base | Representation |
---|---|
bin | 1110001001001100100100… |
… | …10000111111111110000111 |
3 | 11002010100111121102101212022 |
4 | 13010212102100333332013 |
5 | 13034040013400321244 |
6 | 150052112133313355 |
7 | 6360032200665035 |
oct | 704462220777607 |
9 | 132110447371768 |
10 | 31102312120199 |
11 | 9a014643a1191 |
12 | 35a3a0549585b |
13 | 1447c21244288 |
14 | 797507959555 |
15 | 38e0987426ee |
hex | 1c499243ff87 |
31102312120199 has 4 divisors (see below), whose sum is σ = 31146680611800. Its totient is φ = 31057943628600.
The previous prime is 31102312120171. The next prime is 31102312120241. The reversal of 31102312120199 is 99102121320113.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 31102312120199 - 224 = 31102295342983 is a prime.
It is a super-2 number, since 2×311023121201992 (a number of 28 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (31102312120129) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 22184244749 + ... + 22184246150.
It is an arithmetic number, because the mean of its divisors is an integer number (7786670152950).
Almost surely, 231102312120199 is an apocalyptic number.
31102312120199 is a deficient number, since it is larger than the sum of its proper divisors (44368491601).
31102312120199 is an equidigital number, since it uses as much as digits as its factorization.
31102312120199 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 44368491600.
The product of its (nonzero) digits is 5832, while the sum is 35.
The spelling of 31102312120199 in words is "thirty-one trillion, one hundred two billion, three hundred twelve million, one hundred twenty thousand, one hundred ninety-nine".
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