Base | Representation |
---|---|
bin | 1110001001001100100100… |
… | …10001101111000010110011 |
3 | 11002010100111121210012100111 |
4 | 13010212102101233002303 |
5 | 13034040013423004021 |
6 | 150052112141402151 |
7 | 6360032202430132 |
oct | 704462221570263 |
9 | 132110447705314 |
10 | 31102312313011 |
11 | 9a01464513035 |
12 | 35a3a05569357 |
13 | 1447c212b0c74 |
14 | 7975079a9919 |
15 | 38e09877e8e1 |
hex | 1c499246f0b3 |
31102312313011 has 2 divisors, whose sum is σ = 31102312313012. Its totient is φ = 31102312313010.
The previous prime is 31102312312999. The next prime is 31102312313053. The reversal of 31102312313011 is 11031321320113.
It is a weak prime.
It is an emirp because it is prime and its reverse (11031321320113) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 31102312313011 - 233 = 31093722378419 is a prime.
It is a super-2 number, since 2×311023123130112 (a number of 28 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (31102312313081) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15551156156505 + 15551156156506.
It is an arithmetic number, because the mean of its divisors is an integer number (15551156156506).
Almost surely, 231102312313011 is an apocalyptic number.
31102312313011 is a deficient number, since it is larger than the sum of its proper divisors (1).
31102312313011 is an equidigital number, since it uses as much as digits as its factorization.
31102312313011 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 324, while the sum is 22.
Adding to 31102312313011 its reverse (11031321320113), we get a palindrome (42133633633124).
The spelling of 31102312313011 in words is "thirty-one trillion, one hundred two billion, three hundred twelve million, three hundred thirteen thousand, eleven".
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