3110301300113 has 12 divisors (see below), whose sum is σ = 3808532205360. Its totient is φ = 2525658197832.

The previous prime is 3110301300097. The next prime is 3110301300167. The reversal of 3110301300113 is 3110031030113.

3110301300113 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is not a de Polignac number, because 3110301300113 - 2⁴ = 3110301300097 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 3110301300091 and 3110301300100.

It is not an unprimeable number, because it can be changed into a prime (3110301330113) by changing a digit.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 1670407931 + ... + 1670409792.

It is an arithmetic number, because the mean of its divisors is an integer number (317377683780).

Almost surely, 2^{3110301300113} is an apocalyptic number.

It is an amenable number.

3110301300113 is a deficient number, since it is larger than the sum of its proper divisors (698230905247).

3110301300113 is a wasteful number, since it uses less digits than its factorization.

3110301300113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3340817756 (or 3340817749 counting only the distinct ones).

The product of its (nonzero) digits is 81, while the sum is 17.

Adding to 3110301300113 its reverse (3110031030113), we get a palindrome (6220332330226).

The spelling of 3110301300113 in words is "three trillion, one hundred ten billion, three hundred one million, three hundred thousand, one hundred thirteen".