Base | Representation |
---|---|
bin | 11100111101111001… |
… | …000001101000000001 |
3 | 2222021122000201101222 |
4 | 130331321001220001 |
5 | 1002144400130423 |
6 | 22142200004425 |
7 | 2150523146426 |
oct | 347571015001 |
9 | 88248021358 |
10 | 31103130113 |
11 | 122109a7010 |
12 | 6040460715 |
13 | 2c18aa0703 |
14 | 1710b5dd4d |
15 | c208cc3c8 |
hex | 73de41a01 |
31103130113 has 32 divisors (see below), whose sum is σ = 36497029248. Its totient is φ = 26193024000.
The previous prime is 31103130109. The next prime is 31103130127.
31103130113 is nontrivially palindromic in base 10.
It is not a de Polignac number, because 31103130113 - 22 = 31103130109 is a prime.
It is a Harshad number since it is a multiple of its sum of digits (17).
It is a Duffinian number.
It is a Curzon number.
It is a junction number, because it is equal to n+sod(n) for n = 31103130091 and 31103130100.
It is not an unprimeable number, because it can be changed into a prime (31103130193) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 3136463 + ... + 3146363.
It is an arithmetic number, because the mean of its divisors is an integer number (1140532164).
Almost surely, 231103130113 is an apocalyptic number.
It is an amenable number.
31103130113 is a deficient number, since it is larger than the sum of its proper divisors (5393899135).
31103130113 is a wasteful number, since it uses less digits than its factorization.
31103130113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 10193.
The product of its (nonzero) digits is 81, while the sum is 17.
The spelling of 31103130113 in words is "thirty-one billion, one hundred three million, one hundred thirty thousand, one hundred thirteen".
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