Base | Representation |
---|---|
bin | 1110001001001110000110… |
… | …01100110101101011011011 |
3 | 11002010102121211021011022222 |
4 | 13010213003030311223123 |
5 | 13034043204034104201 |
6 | 150052325422134255 |
7 | 6360061430214146 |
oct | 704470314655333 |
9 | 132112554234288 |
10 | 31103133113051 |
11 | 9a0184587027a |
12 | 35a3bb442138b |
13 | 144802236746c |
14 | 7975849cb05d |
15 | 38e0e586491b |
hex | 1c49c3335adb |
31103133113051 has 2 divisors, whose sum is σ = 31103133113052. Its totient is φ = 31103133113050.
The previous prime is 31103133112991. The next prime is 31103133113077. The reversal of 31103133113051 is 15031133130113.
It is an a-pointer prime, because the next prime (31103133113077) can be obtained adding 31103133113051 to its sum of digits (26).
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-31103133113051 is a prime.
It is a Sophie Germain prime.
It is a self number, because there is not a number n which added to its sum of digits gives 31103133113051.
It is not a weakly prime, because it can be changed into another prime (31103133113851) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15551566556525 + 15551566556526.
It is an arithmetic number, because the mean of its divisors is an integer number (15551566556526).
Almost surely, 231103133113051 is an apocalyptic number.
31103133113051 is a deficient number, since it is larger than the sum of its proper divisors (1).
31103133113051 is an equidigital number, since it uses as much as digits as its factorization.
31103133113051 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1215, while the sum is 26.
Adding to 31103133113051 its reverse (15031133130113), we get a palindrome (46134266243164).
The spelling of 31103133113051 in words is "thirty-one trillion, one hundred three billion, one hundred thirty-three million, one hundred thirteen thousand, fifty-one".
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