311043314011 has 8 divisors (see below), whose sum is σ = 311840567280. Its totient is φ = 310246490112.

The previous prime is 311043314009. The next prime is 311043314053. The reversal of 311043314011 is 110413340113.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a 14-Lehmer number, since φ(311043314011) divides (311043314011-1)¹⁴.

It is a cyclic number.

It is not a de Polignac number, because 311043314011 - 2¹ = 311043314009 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (311043314111) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1369291 + ... + 1580203.

It is an arithmetic number, because the mean of its divisors is an integer number (38980070910).

Almost surely, 2^311043314011 is an apocalyptic number.

311043314011 is a deficient number, since it is larger than the sum of its proper divisors (797253269).

311043314011 is a wasteful number, since it uses less digits than its factorization.

311043314011 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 214685.

The product of its (nonzero) digits is 432, while the sum is 22.

Adding to 311043314011 its reverse (110413340113), we get a palindrome (421456654124).

The spelling of 311043314011 in words is "three hundred eleven billion, forty-three million, three hundred fourteen thousand, eleven".