3111002113 has 4 divisors (see below), whose sum is σ = 3131604928. Its totient is φ = 3090399300.

The previous prime is 3111002093. The next prime is 3111002119. The reversal of 3111002113 is 3112001113.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 3111002113 - 2²¹ = 3108904961 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 3111002093 and 3111002102.

It is not an unprimeable number, because it can be changed into a prime (3111002119) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 10301181 + ... + 10301482.

It is an arithmetic number, because the mean of its divisors is an integer number (782901232).

Almost surely, 2^3111002113 is an apocalyptic number.

It is an amenable number.

3111002113 is a deficient number, since it is larger than the sum of its proper divisors (20602815).

3111002113 is a wasteful number, since it uses less digits than its factorization.

3111002113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 20602814.

The product of its (nonzero) digits is 18, while the sum is 13.

The square root of 3111002113 is about 55776.3580112578. The cubic root of 3111002113 is about 1459.8226645499.

Adding to 3111002113 its reverse (3112001113), we get a palindrome (6223003226).

The spelling of 3111002113 in words is "three billion, one hundred eleven million, two thousand, one hundred thirteen".