Base | Representation |
---|---|
bin | 100011010111100100010011… |
… | …0101011010000000010001111 |
3 | 1111210112002102212220021201112 |
4 | 1012233020212223100002033 |
5 | 311234100012324144133 |
6 | 3021354232254002235 |
7 | 122346254154353261 |
oct | 10657104653200217 |
9 | 1453462385807645 |
10 | 311102309990543 |
11 | 90143826629625 |
12 | 2aa858661a637b |
13 | 10478a8ba9abc6 |
14 | 56b7609b3bb31 |
15 | 25e7741e49648 |
hex | 11af226ad008f |
311102309990543 has 2 divisors, whose sum is σ = 311102309990544. Its totient is φ = 311102309990542.
The previous prime is 311102309990531. The next prime is 311102309990611. The reversal of 311102309990543 is 345099903201113.
It is a weak prime.
It is an emirp because it is prime and its reverse (345099903201113) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 311102309990543 - 222 = 311102305796239 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 311102309990491 and 311102309990500.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (311102309990443) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 155551154995271 + 155551154995272.
It is an arithmetic number, because the mean of its divisors is an integer number (155551154995272).
Almost surely, 2311102309990543 is an apocalyptic number.
311102309990543 is a deficient number, since it is larger than the sum of its proper divisors (1).
311102309990543 is an equidigital number, since it uses as much as digits as its factorization.
311102309990543 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 787320, while the sum is 50.
The spelling of 311102309990543 in words is "three hundred eleven trillion, one hundred two billion, three hundred nine million, nine hundred ninety thousand, five hundred forty-three".
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