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3111030301213 is a prime number
BaseRepresentation
bin101101010001010111110…
…110110010001000011101
3102000102010001100222101101
4231101113312302020131
5401432342224114323
610341104304113101
7440523142150132
oct55212766621035
912012101328341
103111030301213
11a9a42055639a
12422b31905791
131974a46160a3
14aa808c74589
1555dd2005dad
hex2d457db221d

3111030301213 has 2 divisors, whose sum is σ = 3111030301214. Its totient is φ = 3111030301212.

The previous prime is 3111030301199. The next prime is 3111030301217. The reversal of 3111030301213 is 3121030301113.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 2931019328484 + 180010972729 = 1712022^2 + 424277^2 .

It is an emirp because it is prime and its reverse (3121030301113) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-3111030301213 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (3111030301217) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1555515150606 + 1555515150607.

It is an arithmetic number, because the mean of its divisors is an integer number (1555515150607).

Almost surely, 23111030301213 is an apocalyptic number.

It is an amenable number.

3111030301213 is a deficient number, since it is larger than the sum of its proper divisors (1).

3111030301213 is an equidigital number, since it uses as much as digits as its factorization.

3111030301213 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 162, while the sum is 19.

Adding to 3111030301213 its reverse (3121030301113), we get a palindrome (6232060602326).

The spelling of 3111030301213 in words is "three trillion, one hundred eleven billion, thirty million, three hundred one thousand, two hundred thirteen".