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311103320102053 is a prime number
BaseRepresentation
bin100011010111100100110001…
…0111000100001010010100101
31111210112012001021121021012221
41012233021202320201102211
5311234104044421231203
63021354520420112341
7122346321201226633
oct10657114270412245
91453465037537187
10311103320102053
11901441a4829326
122aa85aa85356b1
1310478bc013861b
1456b76a3d5c353
1525e77a0976abd
hex11af262e214a5

311103320102053 has 2 divisors, whose sum is σ = 311103320102054. Its totient is φ = 311103320102052.

The previous prime is 311103320101969. The next prime is 311103320102161. The reversal of 311103320102053 is 350201023301113.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 264225772730529 + 46877547371524 = 16255023^2 + 6846718^2 .

It is an emirp because it is prime and its reverse (350201023301113) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 311103320102053 - 217 = 311103319970981 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (311103320172053) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 155551660051026 + 155551660051027.

It is an arithmetic number, because the mean of its divisors is an integer number (155551660051027).

Almost surely, 2311103320102053 is an apocalyptic number.

It is an amenable number.

311103320102053 is a deficient number, since it is larger than the sum of its proper divisors (1).

311103320102053 is an equidigital number, since it uses as much as digits as its factorization.

311103320102053 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1620, while the sum is 25.

Adding to 311103320102053 its reverse (350201023301113), we get a palindrome (661304343403166).

The spelling of 311103320102053 in words is "three hundred eleven trillion, one hundred three billion, three hundred twenty million, one hundred two thousand, fifty-three".