311104043331 has 24 divisors (see below), whose sum is σ = 454855286784. Its totient is φ = 188905664640.

The previous prime is 311104043329. The next prime is 311104043389. The reversal of 311104043331 is 133340401113.

It is not a de Polignac number, because 311104043331 - 2¹ = 311104043329 is a prime.

It is a super-2 number, since 2×311104043331² (a number of 24 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (311104043311) by changing a digit.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 5760675 + ... + 5814428.

It is an arithmetic number, because the mean of its divisors is an integer number (18952303616).

Almost surely, 2^311104043331 is an apocalyptic number.

311104043331 is a gapful number since it is divisible by the number (31) formed by its first and last digit.

311104043331 is a deficient number, since it is larger than the sum of its proper divisors (143751243453).

311104043331 is a wasteful number, since it uses less digits than its factorization.

311104043331 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 11575171 (or 11575154 counting only the distinct ones).

The product of its (nonzero) digits is 1296, while the sum is 24.

Adding to 311104043331 its reverse (133340401113), we get a palindrome (444444444444).

The spelling of 311104043331 in words is "three hundred eleven billion, one hundred four million, forty-three thousand, three hundred thirty-one".