311104313131 has 2 divisors, whose sum is σ = 311104313132. Its totient is φ = 311104313130.

The previous prime is 311104313101. The next prime is 311104313159. The reversal of 311104313131 is 131313401113.

It is a strong prime.

It is an emirp because it is prime and its reverse (131313401113) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 311104313131 - 2⁵ = 311104313099 is a prime.

It is a super-2 number, since 2×311104313131² (a number of 24 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (311104313101) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 155552156565 + 155552156566.

It is an arithmetic number, because the mean of its divisors is an integer number (155552156566).

Almost surely, 2^311104313131 is an apocalyptic number.

311104313131 is a deficient number, since it is larger than the sum of its proper divisors (1).

311104313131 is an equidigital number, since it uses as much as digits as its factorization.

311104313131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 324, while the sum is 22.

Adding to 311104313131 its reverse (131313401113), we get a palindrome (442417714244).

The spelling of 311104313131 in words is "three hundred eleven billion, one hundred four million, three hundred thirteen thousand, one hundred thirty-one".