311111112133 has 2 divisors, whose sum is σ = 311111112134. Its totient is φ = 311111112132.

The previous prime is 311111112089. The next prime is 311111112181. The reversal of 311111112133 is 331211111113.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 308826941284 + 2284170849 = 555722^2 + 47793^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-311111112133 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 311111112133.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (311111110133) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 155555556066 + 155555556067.

It is an arithmetic number, because the mean of its divisors is an integer number (155555556067).

Almost surely, 2^311111112133 is an apocalyptic number.

It is an amenable number.

311111112133 is a deficient number, since it is larger than the sum of its proper divisors (1).

311111112133 is an equidigital number, since it uses as much as digits as its factorization.

311111112133 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 54, while the sum is 19.

Adding to 311111112133 its reverse (331211111113), we get a palindrome (642322223246).

The spelling of 311111112133 in words is "three hundred eleven billion, one hundred eleven million, one hundred twelve thousand, one hundred thirty-three".