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311111332117 is a prime number
BaseRepresentation
bin1001000011011111010…
…11100011000100010101
31002202000212212011221021
410201233223203010111
520044124000111432
6354531135321141
731322425455535
oct4415753430425
91082025764837
10311111332117
1110aa3a266603
12503666801b1
1323450b36a41
14110b4b134c5
15815cde0697
hex486fae3115

311111332117 has 2 divisors, whose sum is σ = 311111332118. Its totient is φ = 311111332116.

The previous prime is 311111332087. The next prime is 311111332123. The reversal of 311111332117 is 711233111113.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 308503595761 + 2607736356 = 555431^2 + 51066^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-311111332117 is a prime.

It is a super-2 number, since 2×3111113321172 (a number of 24 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 311111332091 and 311111332100.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (311111332127) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 155555666058 + 155555666059.

It is an arithmetic number, because the mean of its divisors is an integer number (155555666059).

Almost surely, 2311111332117 is an apocalyptic number.

It is an amenable number.

311111332117 is a deficient number, since it is larger than the sum of its proper divisors (1).

311111332117 is an equidigital number, since it uses as much as digits as its factorization.

311111332117 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 378, while the sum is 25.

The spelling of 311111332117 in words is "three hundred eleven billion, one hundred eleven million, three hundred thirty-two thousand, one hundred seventeen".