Base | Representation |
---|---|
bin | 10010100010110… |
… | …101000001111101 |
3 | 210200102112101212 |
4 | 102202311001331 |
5 | 1114121314442 |
6 | 50512214205 |
7 | 10465322246 |
oct | 2242650175 |
9 | 720375355 |
10 | 311119997 |
11 | 14a68a071 |
12 | 8823a365 |
13 | 4c5c2396 |
14 | 2d469ccd |
15 | 1c4a8a82 |
hex | 128b507d |
311119997 has 2 divisors, whose sum is σ = 311119998. Its totient is φ = 311119996.
The previous prime is 311119961. The next prime is 311120027. The reversal of 311119997 is 799911113.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 221741881 + 89378116 = 14891^2 + 9454^2 .
It is an emirp because it is prime and its reverse (799911113) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 311119997 - 212 = 311115901 is a prime.
It is equal to p16821788 and since 311119997 and 16821788 have the same sum of digits, it is a Honaker prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (311119957) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 155559998 + 155559999.
It is an arithmetic number, because the mean of its divisors is an integer number (155559999).
Almost surely, 2311119997 is an apocalyptic number.
It is an amenable number.
311119997 is a deficient number, since it is larger than the sum of its proper divisors (1).
311119997 is an equidigital number, since it uses as much as digits as its factorization.
311119997 is an evil number, because the sum of its binary digits is even.
The product of its digits is 15309, while the sum is 41.
The square root of 311119997 is about 17638.5939632387. The cubic root of 311119997 is about 677.6040222807.
The spelling of 311119997 in words is "three hundred eleven million, one hundred nineteen thousand, nine hundred ninety-seven".
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