Base | Representation |
---|---|
bin | 1001000011100000011… |
… | …01000101000011110101 |
3 | 1002202001111101202112020 |
4 | 10201300031011003311 |
5 | 20044133222401401 |
6 | 354532051543353 |
7 | 31322563255365 |
oct | 4416015050365 |
9 | 1082044352466 |
10 | 311120122101 |
11 | 10aa4421a658 |
12 | 503695bab59 |
13 | 234528c3909 |
14 | 110b5d609a5 |
15 | 815da79d36 |
hex | 48703450f5 |
311120122101 has 128 divisors (see below), whose sum is σ = 473776128000. Its totient is φ = 180652032000.
The previous prime is 311120122091. The next prime is 311120122109. The reversal of 311120122101 is 101221021113.
It is not a de Polignac number, because 311120122101 - 27 = 311120121973 is a prime.
It is a super-2 number, since 2×3111201221012 (a number of 24 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (311120122109) by changing a digit.
It is a polite number, since it can be written in 127 ways as a sum of consecutive naturals, for example, 1148044596 + ... + 1148044866.
It is an arithmetic number, because the mean of its divisors is an integer number (3701376000).
Almost surely, 2311120122101 is an apocalyptic number.
311120122101 is a gapful number since it is divisible by the number (31) formed by its first and last digit.
It is an amenable number.
311120122101 is a deficient number, since it is larger than the sum of its proper divisors (162656005899).
311120122101 is a wasteful number, since it uses less digits than its factorization.
311120122101 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 651.
The product of its (nonzero) digits is 24, while the sum is 15.
Adding to 311120122101 its reverse (101221021113), we get a palindrome (412341143214).
The spelling of 311120122101 in words is "three hundred eleven billion, one hundred twenty million, one hundred twenty-two thousand, one hundred one".
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