Base | Representation |
---|---|
bin | 1001000011100000100… |
… | …00011011111001000011 |
3 | 1002202001120001110120222 |
4 | 10201300100123321003 |
5 | 20044133434031201 |
6 | 354532122453255 |
7 | 31322603612006 |
oct | 4416020337103 |
9 | 1082046043528 |
10 | 311121002051 |
11 | 10aa44770792 |
12 | 5036996422b |
13 | 23452b412b2 |
14 | 110b610d53d |
15 | 815dba091b |
hex | 487041be43 |
311121002051 has 2 divisors, whose sum is σ = 311121002052. Its totient is φ = 311121002050.
The previous prime is 311121001979. The next prime is 311121002081. The reversal of 311121002051 is 150200121113.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-311121002051 is a prime.
It is not a weakly prime, because it can be changed into another prime (311121002081) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 155560501025 + 155560501026.
It is an arithmetic number, because the mean of its divisors is an integer number (155560501026).
Almost surely, 2311121002051 is an apocalyptic number.
311121002051 is a deficient number, since it is larger than the sum of its proper divisors (1).
311121002051 is an equidigital number, since it uses as much as digits as its factorization.
311121002051 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 60, while the sum is 17.
Adding to 311121002051 its reverse (150200121113), we get a palindrome (461321123164).
The spelling of 311121002051 in words is "three hundred eleven billion, one hundred twenty-one million, two thousand, fifty-one".
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