Base | Representation |
---|---|
bin | 11100111110011011… |
… | …010100101100011001 |
3 | 2222022020221111201222 |
4 | 130332123110230121 |
5 | 1002204200333423 |
6 | 22143120421425 |
7 | 2150662444313 |
oct | 347633245431 |
9 | 88266844658 |
10 | 31112121113 |
11 | 12215a88097 |
12 | 6043477875 |
13 | 2c1a8cac28 |
14 | 17120207b3 |
15 | c215a63c8 |
hex | 73e6d4b19 |
31112121113 has 2 divisors, whose sum is σ = 31112121114. Its totient is φ = 31112121112.
The previous prime is 31112121101. The next prime is 31112121151.
31112121113 is nontrivially palindromic in base 10.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 29971573129 + 1140547984 = 173123^2 + 33772^2 .
It is a palprime.
It is a cyclic number.
It is not a de Polignac number, because 31112121113 - 24 = 31112121097 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 31112121091 and 31112121100.
It is not a weakly prime, because it can be changed into another prime (31112121913) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15556060556 + 15556060557.
It is an arithmetic number, because the mean of its divisors is an integer number (15556060557).
Almost surely, 231112121113 is an apocalyptic number.
It is an amenable number.
31112121113 is a deficient number, since it is larger than the sum of its proper divisors (1).
31112121113 is an equidigital number, since it uses as much as digits as its factorization.
31112121113 is an evil number, because the sum of its binary digits is even.
The product of its digits is 36, while the sum is 17.
The spelling of 31112121113 in words is "thirty-one billion, one hundred twelve million, one hundred twenty-one thousand, one hundred thirteen".
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